(d^2-d+5)-(2d+5)=

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Solution for (d^2-d+5)-(2d+5)= equation:


Simplifying
(d2 + -1d + 5) + -1(2d + 5) = 0

Reorder the terms:
(5 + -1d + d2) + -1(2d + 5) = 0

Remove parenthesis around (5 + -1d + d2)
5 + -1d + d2 + -1(2d + 5) = 0

Reorder the terms:
5 + -1d + d2 + -1(5 + 2d) = 0
5 + -1d + d2 + (5 * -1 + 2d * -1) = 0
5 + -1d + d2 + (-5 + -2d) = 0

Reorder the terms:
5 + -5 + -1d + -2d + d2 = 0

Combine like terms: 5 + -5 = 0
0 + -1d + -2d + d2 = 0
-1d + -2d + d2 = 0

Combine like terms: -1d + -2d = -3d
-3d + d2 = 0

Solving
-3d + d2 = 0

Solving for variable 'd'.

Factor out the Greatest Common Factor (GCF), 'd'.
d(-3 + d) = 0

Subproblem 1

Set the factor 'd' equal to zero and attempt to solve: Simplifying d = 0 Solving d = 0 Move all terms containing d to the left, all other terms to the right. Simplifying d = 0

Subproblem 2

Set the factor '(-3 + d)' equal to zero and attempt to solve: Simplifying -3 + d = 0 Solving -3 + d = 0 Move all terms containing d to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + d = 0 + 3 Combine like terms: -3 + 3 = 0 0 + d = 0 + 3 d = 0 + 3 Combine like terms: 0 + 3 = 3 d = 3 Simplifying d = 3

Solution

d = {0, 3}

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